Question:medium

The equation of the tangent to the curve \(y=x^3\) at \((1,1)\) is

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To find tangent equation, first find slope using derivative, then use \(y-y_1=m(x-x_1)\).

Updated On: May 7, 2026

\(3x-y+2=0\)
\(x-10y-50=0\)
\(3x-y-2=0\)
\(x-10y+50=0\)

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The Correct Option is C

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