Question:medium
The equation of the line passing through the point $(-4,\,2)$ and the centre of the circle $2x^2 + 2y^2 - 8y = 7$ is
The equation of the line passing through the point $(-4,\,2)$ and the centre of the circle $2x^2 + 2y^2 - 8y = 7$ is
Show Hint
Always divide the circle equation by the coefficient of $x^2$ (and $y^2$) before completing the square to find the centre. The centre is $(-g,\,-f)$ in the general form $x^2+y^2+2gx+2fy+c=0$.
Updated On: Apr 25, 2026
- $x + 3y = 2$
- $y = 2$
- $x = -4$
- $x + y = -2$
- $y = -2$
Show Solution
The Correct Option is B
Solution and Explanation
Was this answer helpful?
0
Top Questions on circle
- The locus of the point of intersection of the lines \(x = a(1 - t^2)/(1 + t^2)\) and \(y = 2at/(1 + t^2)\) (t being a parameter) represents:
- BITSAT - 2024
- Mathematics
- circle
- If the straight line $2x + 3y - 1 = 0$, $x + 2y - 1 = 0$ and $ax + by - 1 = 0$ form a triangle with origin as orthocentre, then $(a,b)$ is equal to:
- BITSAT - 2024
- Mathematics
- circle
- The distance from the origin to the image of $(1,1)$ with respect to the line $x + y + 5 = 0$ is:
- BITSAT - 2024
- Mathematics
- circle
- A(3,2,0), B(5,3,2), C(-9,6,-3) are three points forming a triangle. AD, the bisector of angle $BAC$ meets BC in D. Find the coordinates of D:
- BITSAT - 2024
- Mathematics
- circle
- Want to practice more? Try solving extra ecology questions todayView All Questions
