Question:medium

The enthalpy of sublimation of aluminium is \(330\,\text{kJ mol}^{-1}\). Its I\(^\text{st}\), II\(^\text{nd}\) and III\(^\text{rd}\) ionization enthalpies are 580, 1820 and \(2740\,\text{kJ mol}^{-1}\) respectively. How much heat must be supplied in kJ to convert 13.5 g of aluminium into Al\(^{3+}\) ions and electrons at 298 K?

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Always multiply molar enthalpy by number of moles.
Updated On: Mar 24, 2026
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The Correct Option is C

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