Question:medium

The enthalpy change for a reaction at equilibrium is $-20.5$ kJ mol$^{-1}$. Then the entropy change for this equilibrium at 410 K is}

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At equilibrium: $\Delta G=0 \Rightarrow \Delta S = \frac{\Delta H}{T}$
Updated On: May 8, 2026
  • $+50$ JK$^{-1}$ mol$^{-1}$
  • $+55$ JK$^{-1}$ mol$^{-1}$
  • $+75$ JK$^{-1}$ mol$^{-1}$
  • $-50$ JK$^{-1}$ mol$^{-1}$
  • $-55$ JK$^{-1}$ mol$^{-1}$
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The Correct Option is A

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