For hydrogen atom problems based on Bohr’s model, always remember:
\[
E_n \propto \frac{1}{n^2}
\]
If the orbit number becomes twice, the energy becomes one-fourth.
Here:
\[
2 \rightarrow 4
\]
So,
\[
E_4 = \frac{E_2}{4}
\]
which gives:
\[
-328/4 = -82
\]