Question:easy

The element with atomic number 114 has outer shell electron configuration as that of element 'X'. What is X?

Show Hint

Elements of the same group have identical valence shell configurations. Identify the group first, then match the option from that group.
Updated On: Jun 15, 2026
  • Ar
  • Ge
  • Se
  • Ti
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Identify element 114.
The element with atomic number 114 is Flerovium, symbol Fl.
Step 2: Place it in the periodic table.
Flerovium sits in Group 14, directly below lead, so it shares that group's valence pattern.
Step 3: Recall the Group 14 valence configuration.
Every Group 14 element ends in \[ ns^2 np^2 \] giving four electrons in the outer shell.
Step 4: List the Group 14 family.
These are carbon, silicon, germanium, tin, lead, and flerovium. The matching outer shell must also be $ns^2 np^2$.
Step 5: Screen the options.
Argon is a noble gas (Group 18), selenium is Group 16, and titanium is a Group 4 transition metal. Only germanium belongs to Group 14.
Step 6: Confirm by configuration.
Germanium has $4s^2 4p^2$, analogous to flerovium's $7s^2 7p^2$, so X is germanium, option 2.
\[ \boxed{\text{Ge}} \]
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