Question:medium
The electric field strength in \( \text{N C}^{-1} \) that is required to just prevent a water drop carrying a charge \( 1.6 \times 10^{-19} \) C from falling under gravity is (\( g = 9.8 \, \text{m s}^{-2} \), mass of water drop = \( 0.0016 \) g)
The electric field strength in \( \text{N C}^{-1} \) that is required to just prevent a water drop carrying a charge \( 1.6 \times 10^{-19} \) C from falling under gravity is (\( g = 9.8 \, \text{m s}^{-2} \), mass of water drop = \( 0.0016 \) g)
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Equilibrium → set electric force equal to weight.
Updated On: May 2, 2026
- $9.8 \times 10^{-16}$
- $9.8 \times 10^{16}$
- $9.8 \times 10^{-13}$
- $9.8 \times 10^{13}$
- $9.8 \times 10^{10}$
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The Correct Option is
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