Question:medium

The eccentricity of the conic $ \frac{5}{r} = 2 + 3\cos\theta + 4\sin\theta $ is

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$a\cos \theta + b\sin \theta$ can be written as $\sqrt{a^2+b^2}\cos(\theta - \phi)$.

Updated On: Apr 10, 2026

$\frac{4}{2}$
1
$\frac{5}{2}$
0

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The Correct Option is C

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The eccentricity of the conic \( \frac{5}{r} = 2 + 3\cos\theta + 4\sin\theta \) is

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The Correct Option is C

Solution and Explanation

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