Question:medium

The eccentricity of the conic \(9x^2 - 16y^2 = 144\) is

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Hyperbola: \(e>1\) always.
Updated On: Apr 18, 2026
  • 4/5
  • 4/3
  • 5/4
  • \(\sqrt{7}\)
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
The given equation represents a hyperbola. We need to convert it to standard form \( \frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1 \) to identify the semi-axes and then calculate the eccentricity.
: Key Formula or Approach:
Eccentricity of a hyperbola: \( e = \sqrt{1 + \frac{b^{2}}{a^{2}}} \).
Step 2: Detailed Explanation:
Start with the equation: \[ 9x^{2} - 16y^{2} = 144 \] Divide both sides by 144 to get the standard form: \[ \frac{9x^{2}}{144} - \frac{16y^{2}}{144} = 1 \] \[ \frac{x^{2}}{16} - \frac{y^{2}}{9} = 1 \] Comparing with standard form \( \frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1 \): \[ a^{2} = 16 \text{ and } b^{2} = 9 \] Now calculate eccentricity \( e \): \[ e = \sqrt{1 + \frac{9}{16}} \] \[ e = \sqrt{\frac{16 + 9}{16}} \] \[ e = \sqrt{\frac{25}{16}} = \frac{5}{4} \].
Step 3: Final Answer:
The eccentricity is 5/4.
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