Question:medium

Let P be a point on the parabola, \( x^2 = 4y \). If the distance of P from the centre of the circle, \( x^2 + y^2 + 6x + 8 = 0 \) is minimum, then the equation of the tangent to the parabola at P, is :

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For minimum distance between a curve and a point, the normal at that point must pass through the given point. Finding 't' by inspection in a cubic equation often saves time. \

Updated On: Apr 19, 2026

\( x + 4y - 2 = 0 \)
\( x + y + 1 = 0 \)
\( x - y + 3 = 0 \)
\( x + 2y = 0 \)

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The Correct Option is B

Solution and Explanation

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Let P be a point on the parabola, \( x^2 = 4y \). If the distance of P from the centre of the circle, \( x^2 + y^2 + 6x + 8 = 0 \) is minimum, then the equation of the tangent to the parabola at P, is :

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The Correct Option is B

Solution and Explanation

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