Question:medium

The domain and range of $f(x) = \frac{1}{\sqrt{|x|-x^2}}$ are A and B respectively. Then $A \cup B = $ ?

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For expressions like $\frac{1}{\sqrt{g(x)}}$, always ensure $g(x)>0$ (not $\geq 0$), because the denominator cannot be zero.

Updated On: Mar 30, 2026

$\mathbb{R} - \{-1,0,1\}$
$(-1, \infty) - \{0,1\}$
$(-1,0) \cup (0,1) \cup [2, \infty)$
$(-1,1) \cup [2, \infty)$

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The Correct Option is C

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