Question:medium

The distance of the point (1, 6, 2) from the point of intersection of the line $(x-2)/3 = (y+1)/4 = (z-2)/12$ and the plane $x - y + z = 16$ is:

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First find the point of intersection, then apply the 3D distance formula.
Updated On: Jun 26, 2026
  • 11 units
  • 12 units
  • 13 units
  • 14 units
Show Solution

The Correct Option is C

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