The problem is to find the direction cosines of any normal to the xy-plane. To solve this, let's delve into the concept of direction cosines and the geometry of the coordinate planes:
Concepts:
- The xy-plane is defined by the equation \(z = 0\). Any normal to this plane is along the z-axis.
- Direction cosines of a vector are the cosines of the angles made by the vector with the coordinate axes (x, y, and z).
Step-by-step Explanation:
- A normal to the xy-plane can be represented by the vector along the z-axis, which has components (0, 0, 1).
- The angle made by this vector with the:
- x-axis is 90 degrees (cos(90) = 0),
- y-axis is 90 degrees (cos(90) = 0),
- z-axis is 0 degrees (cos(0) = 1).
- Thus, the direction cosines of this normal vector are (0, 0, 1).
Conclusion:
The direction cosines of any normal to the xy-plane are (0, 0, 1), which matches the correct answer.
Therefore, the correct answer is:
0, 0, 1