Question:medium

The diameters of circles (in mm) drawn in a design are given below

DiametersNo. of children
33-3615
37-4017
41-4421
45-4822
49-5225

Updated On: Jan 22, 2026
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Solution and Explanation

Class IntervalFrequency \(f_i\)\(mid-point\,x_i\)\(y_i=\frac{x_i-42.5}{4}\)\(f_i^2\)\(f_iy_i\)\(f_iy_1^2\)
32.5-36.51534.5-24-3060
36.5-40.51738.5-11-1717
40.5-44.52142.50000
44.5-48.52246.5112222
48.5-52.52550.52450100
 100   25199

Here, N = 100, h = 4 

Let the assumed mean, A, be 42.5

Mean, \(\bar{x}=A\frac{\sum_{i=1}^5f_ix_i}{n}×h=42.5+\frac{25}{100}×4=43.5\) 

Variance (σ2) = \(\frac{h^2}{N^2}[N\sum_{i=1}^5f_iy_i^2-(\sum_{i=1}^5f_iy_i)^2]\)

\(=\frac{16}{10000}[100×199-(25)^2]\)

\(=\frac{16}{10000}[19900-625]\)

\(=\frac{16}{1000}×19275\)

\(=30.84\)

\(Standard\,\,deviation\.(σ) =5.55\)

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