Step 1: Outer then inner:
$\dfrac{d}{dx}\log_8 u = \dfrac{1}{u\log 8}\cdot u'$ with $u = \log_5 x$.
Step 2: Inner derivative:
$u' = \dfrac{1}{x\log5}$ and $u = \dfrac{\log x}{\log5}$, so $\dfrac{u'}{u} = \dfrac{1}{x\log x}$.
Step 3: Combine:
$\dfrac{dy}{dx} = \dfrac{1}{\log8}\cdot\dfrac{1}{x\log x}$, option (D).
Final Answer:
The derivative is 1/(x log 8 log x).
\[ \boxed{\text{(D) }\dfrac{1}{x\log 8\,\log x}} \]