Step 1: Identify the network type. The circuit is a bridge of resistors fed by a $5$ V source. To find the current from the source we first reduce the whole network to one equivalent resistance.
Step 2: Check the bridge balance. In this arrangement the bridge is balanced or symmetric, which lets us combine the resistors cleanly without solving complicated loops. Step 3: Reduce step by step. Combining the series and parallel parts of the balanced bridge, the network collapses to a single value. \[ R_{eq} = 10\,\Omega \] Step 4: Bring in Ohm's law. The current drawn from the source is voltage over total resistance. \[ I = \frac{V}{R_{eq}} \] Step 5: Put in the numbers. \[ I = \frac{5}{10} \] Step 6: State the current. \[ I = 0.5\,\text{A} \] \[ \boxed{0.5\,\text{A}} \]
