Question

The correct order of spin-only magnetic moments among the following is: [Given: Atomic numbers: Mn = 25, Fe = 26, Co = 27]

• A. \( [\text{Fe(CN)}_6]^{4+} \) $>$ \( [\text{MnCl}_4]^{2-} \) $>$ \( [\text{CoCl}_4]^{2-} \)
• B. \( [\text{MnCl}_4]^{2-} \) $>$ \( [\text{CoCl}_4]^{2-} \) $>$ \( [\text{Fe(CN)}_6]^{4-} \)
  $$
• C. \( [\text{Fe(CN)}_6]^{4+} \) $>$ \( [\text{CoCl}_4]^{2-} \) $>$ \( [\text{MnCl}_4]^{2-} \)
• D. \( [\text{MnCl}_4]^{2-} \) $>$ \( [\text{Fe(CN)}_6]^{4+} \) $>$ \( [\text{CoCl}_4]^{2-} \)

Hint:

The magnetic moment is directly related to the number of unpaired electrons in the complex. A higher number of unpaired electrons results in a higher magnetic moment.

Answer 1

The Correct Option is B