To determine the correct order of electron gain enthalpies for Cl, F, Te, and Po, we need to understand the concept of electron gain enthalpy, which is the energy change when an electron is added to a neutral atom in the gaseous state to form a negative ion. The more negative the electron gain enthalpy, the greater the tendency of the atom to accept an electron.
Atoms with higher electronegativity and smaller atomic radii typically have more negative electron gain enthalpy values. However, due to the small size of fluorine, there is significant electron-electron repulsion when an extra electron is added, making its electron gain enthalpy less negative than expected.
From the analysis, chlorine has the most negative electron gain enthalpy, followed by fluorine, and then tellurium and polonium. Therefore, the correct order is F < Cl < Te < Po.
In conclusion, the correct order of electron gain enthalpies is: F < Cl < Te < Po.
Given below are two statements:
Statement I: The conversion proceeds well in a less polar medium. \[ {CH}_3{CH}_2{CH}_2{CH}_2{Cl} \xrightarrow{{HO}^-} {CH}_3{CH}_2{CH}_2{CH}_2{OH} + {Cl}^- \] Statement II: The conversion proceeds well in a more polar medium. \[ {CH}_3{CH}_2{CH}_2{CH}_2{Cl} \xrightarrow{{R}_3{N}} {CH}_3{CH}_2{CH}_2{CH}_2{NH}_2 + {Cl}^- \] In the light of the above statements, choose the correct answer from the options given below: