Question:easy

The correct increasing order of wavelength for UV, Visible light, and Microwaves is:

Show Hint

Remember that energy and frequency are inversely proportional to wavelength ($E = h\nu = hc/\lambda$).
Since UV has the highest energy among the three, it must have the shortest wavelength, while Microwaves have the lowest energy and the longest wavelength.
  • UV $\lt $ Visible $\lt $ Microwaves
  • Microwaves $\lt $ Visible $\lt $ UV
  • Visible $\lt $ UV $\lt $ Microwaves
  • UV $\lt $ Microwaves $\lt $ Visible
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Recall the layout of the electromagnetic spectrum.
Ordered by increasing wavelength, the spectrum runs roughly as gamma rays, X-rays, UV, visible light, infrared, microwaves, and radio waves.
Step 2: Place the three given regions on this scale.
UV lies just below visible light in wavelength (roughly 10-400 nm), visible light spans about 400-700 nm, and microwaves lie far beyond both, in the millimetre-to-metre range.
Step 3: Arrange them in increasing order.
Since UV has the shortest wavelength of the three, followed by visible light, and microwaves have by far the longest, the increasing order is UV, then visible, then microwaves.
\[ \boxed{\text{UV} < \text{Visible} < \text{Microwaves}} \]
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