Question

The correct formula of Hinsberg's reagent is:

• A. C\(_6\)H\(_5\)COCl
• B. C\(_6\)H\(_5\)SO\(_2\)Cl
• C. C\(_6\)H\(_5\)CONHCH\(_3\)
• D. C\(_6\)H\(_6\)CH\(_2\)NH\(_2\)

Hint:

{Hinsberg Reagent = Benzenesulphonyl chloride} Formula to remember: \( C_6H_5SO_2Cl \)

Answer 1

The Correct Option is B

The Hinsberg test is used to distinguish between primary, secondary, and tertiary amines. For this interaction, a specific reagent known as Hinsberg's reagent is utilized. Let's explore the options we have and pinpoint the correct chemical formula for Hinsberg's reagent.

1. Option 1: \(C_6H_5COCl\)
   • This compound is Benzoyl chloride. It is generally known for its role in acylation reactions but not as Hinsberg's reagent.
2. Option 2: \(C_6H_5SO_2Cl\)
   • This compound is Benzenesulfonyl chloride. This is the actual formula for Hinsberg's reagent. It reacts with primary and secondary amines to form sulfonamides, which allows for their differentiation.
3. Option 3: \(C_6H_5CONHCH_3\)
   • This is N-methylbenzamide, not related to the Hinsberg test, as it doesn't have the functional groups necessary for distinguishing amine classes.
4. Option 4: \(C_6H_6CH_2NH_2\)
   • This compound is Benzylamine, which is a primary amine and not used as Hinsberg's reagent.

Therefore, the correct formula for Hinsberg's reagent is \(C_6H_5SO_2Cl\) (Benzenesulfonyl chloride).