Step 1: Test option A in both lines:
For line 1: $\frac{2 - 3}{1} = -1$, $\frac{3 - 5}{2} = -1$, $\frac{2 - 1}{-1} = -1$. All equal.
Step 2: Line 2:
$\frac{2 - 4}{2} = -1$, $\frac{3 - 2}{-1} = -1$, $\frac{2 - 4}{2} = -1$. All equal.
So $(2, 3, 2)$ lies on both lines. The other options give unequal ratios.
Final Answer:
The intersection point is $(2, 3, 2)$, option (A).
\[ \boxed{(2,3,2)} \]