Step 1: Basic Principle
A conjugate base is formed when an acid donates a proton (H\(^+\)).
Step 2: Solution Procedure:
H\(_2\)S \(\rightarrow\) H\(^+\) + HS\(^-\)
When H\(_2\)S loses one proton, it forms HS\(^-\). HS\(^-\) is the conjugate base of H\(_2\)S.
S\(^{2-}\) is the conjugate base of HS\(^-\).
Step 3: Required Answer:
The conjugate base of H\(_2\)S is HS\(^-\), option (A).