Question

The conductivity of 0.02 M of KCl solution at 298 K is 0.0123 \(\text{ohm}^{-1} \text{cm}^{-1}\). If the resistance of the cell containing this solution is 120 ohms, what is the value of the cell constant ?

• A. \(1.050 \text{cm}^{-1}\)
• B. \(1.025 \text{cm}^{-1}\)
• C. \(1.376 \text{cm}^{-1}\)
• D. \(1.476 \text{cm}^{-1}\)

Hint:

Cell constant \(= \kappa \times R\).

Answer 1

The Correct Option is D

Step 1: Rearrange
From $\kappa = \dfrac{G^*}{R}$ we get $G^* = \kappa R$.

Step 2: Substitute
$0.0123\times120 = 1.476$ cm$^{-1}$, option (D).

Final Answer:
The cell constant is 1.476 cm$^{-1}$, option (D). \[ \boxed{1.476\ \text{cm}^{-1}} \]