Question

The compound which does not show a simple ratio of atoms is:

• A. Benzene
• B. Acetylene
• C. Hydrogen
• D. Sucrose

Hint:

Sucrose is a disaccharide with a complex molecular structure and does not exhibit a simple ratio of atoms like elemental substances.

Answer 1

The Correct Option is D

Step 1: Concept.
Benzene, acetylene, and hydrogen are each a single small molecule with a plain carbon-to-hydrogen ratio of 1 is to 1, or, for hydrogen, just two identical atoms.

Step 2: Check sucrose separately.
Sucrose, C12H22O11, is a disaccharide built by joining a glucose unit and a fructose unit through a glycosidic bond, so its formula reflects two combined sugar units rather than one simple repeating structure.

Step 3: Final Answer.
Sucrose is the compound that does not show a simple ratio of atoms.

Answer 2

Simply counting the total number of atoms packed into one molecule of each compound also highlights which one is structurally the odd one out.

1. Hydrogen: One molecule of H2 contains just 2 atoms total, among the simplest possible molecular arrangements.
2. Acetylene: One molecule of C2H2 contains 4 atoms total, still a small, simple hydrocarbon.
3. Benzene: One molecule of C6H6 contains 12 atoms total, more than acetylene, but still built from one plain 1 is to 1 carbon-hydrogen ratio in a single ring.
4. Sucrose: One molecule of C12H22O11 contains 45 atoms total across three different elements, carbon, hydrogen, and oxygen, arranged through multiple ring structures and a connecting glycosidic bond. This is a far larger and more elaborate atomic arrangement than the other three compounds show.

Going from 2 atoms in hydrogen up to 45 atoms across three elements in sucrose shows a clear jump in structural complexity that the other three simple hydrocarbons do not share.

So the correct answer is Sucrose.