Question

How many isomers are possible for C$_4$H$_8$Cl$_2$ (including chain and positional)?

• A. 6
• B. 8
• C. 7
• D. 9

Hint:

Consider both chain and positional isomerism when calculating the number of possible isomers.

Answer 1

The Correct Option is B

Isomer Count for \( \text{C}_4\text{H}_8\text{Cl}_2 \)

Isomer Classifications:

• Structural isomers based on carbon skeleton arrangement (e.g., n-butane vs. isobutane)
• Positional isomers detailing chlorine atom locations

1. Derived from n-butane (straight-chain):

Chlorine atom placement possibilities:

• 1,1-dichlorobutane
• 1,2-dichlorobutane (vicinal)
• 1,3-dichlorobutane
• 2,2-dichlorobutane
• 2,3-dichlorobutane

Subtotal = 5 isomers

 

2. Derived from isobutane (branched-chain):

Chlorine atom placement possibilities:

• 1,1-dichloro-2-methylpropane
• 1,2-dichloro-2-methylpropane
• 2,2-dichloro-2-methylpropane

Subtotal = 3 isomers

 

✅ Consolidated Result:

\[ \boxed{8\ \text{isomers}} \]