Question:medium

The complementary function of the differential equation \( y'' + 16y = x \sin px, \, p = 4, \) is given by:

Show Hint

For constant-coefficient differential equations, use the characteristic equation to find the complementary function.
Updated On: Jan 17, 2026
  • \( A \cos(16x) + B \sin(16x), \) where \( A \) and \( B \) are constants.
  • \( A \cos(4x) + B \sin(4x), \) where \( A \) and \( B \) are constants.
  • \( A \cos(8x) + B \sin(8x), \) where \( A \) and \( B \) are constants.
  • \( A \cos(2x) + B \sin(2x), \) where \( A \) and \( B \) are constants.
Show Solution

The Correct Option is B

Solution and Explanation

The complementary function addresses the homogeneous equation \( y'' + 16y = 0 \). Its characteristic equation, \( r^2 + 16 = 0 \), yields roots \( \pm 4i \). The resulting solution is:
\( y_c = A \cos(4x) + B \sin(4x). \)

Was this answer helpful?
0

Top Questions on Physical Chemistry


Questions Asked in CUET (PG) exam