Question:medium

The common difference of the AP : \(\sqrt{2}, 2\sqrt{2}, 3\sqrt{2}, 4\sqrt{2}, \dots\) is :

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Treat radicals like variables. Just as \(2x - x = x\), \(2\sqrt{2} - \sqrt{2} = \sqrt{2}\). Always verify with the third term: \(3\sqrt{2} - 2\sqrt{2} = \sqrt{2}\).
Updated On: Feb 23, 2026
  • \(\sqrt{2}\)
  • 1
  • \(2\sqrt{2}\)
  • \(-\sqrt{2}\)
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The Correct Option is A

Solution and Explanation

To find the common difference of the given arithmetic progression (AP), we first need to recall the definition of an AP. An arithmetic progression is a sequence of numbers such that the difference between any two successive terms is constant. This constant difference is known as the "common difference."

The given AP is: \(\sqrt{2}, 2\sqrt{2}, 3\sqrt{2}, 4\sqrt{2}, \dots\)

  1. Let's identify the first few terms of the sequence:
    • First term, \(a_1 = \sqrt{2}\)
    • Second term, \(a_2 = 2\sqrt{2}\)
    • Third term, \(a_3 = 3\sqrt{2}\)
    • Fourth term, \(a_4 = 4\sqrt{2}\)
  2. To find the common difference \(d\), we subtract the first term from the second term:
    • \(d = \sqrt{2} (2 - 1) = \sqrt{2}\)
  3. You can verify the common difference by checking the difference between subsequent terms:
    • \(d = a_3 - a_2 = 3\sqrt{2} - 2\sqrt{2} = \sqrt{2}\)
    • \(d = a_4 - a_3 = 4\sqrt{2} - 3\sqrt{2} = \sqrt{2}\)

Thus, the common difference of the given arithmetic progression is \(\sqrt{2}\).

Conclusion: The correct option for the common difference is \(\sqrt{2}\).

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