Question:medium

The charge required for the reduction of 1 mol of MnO$_4^-$ to MnO$_2$ is

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When dealing with electrochemical reactions, remember that the number of Faradays required equals the number of moles of electrons involved in the reaction.
Updated On: Jun 13, 2026
  • 1 F
  • 3 F
  • 5 F
  • 6 F
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The Correct Option is C

Solution and Explanation

The reduction of MnO$_4^-$ to MnO$_2$ signifies a Mn oxidation state shift from +7 to +2. The balanced redox equation indicates 5 electrons are needed to reduce 1 mole of MnO$_4^-$. Consequently, 5 Faradays (F) of charge are required for this reduction. Option (3), 5 F, is therefore correct.
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