1. Define Events:
- \( P_1, P_2, P_3 \): \( P, Q, \) and \( R \) are selected as CEO, respectively.
- \( E \): The company experiences an increase in profits.
2. Apply Bayes' Theorem:
The probability to be calculated is:
\[P(P_3 \,|\, E) = \frac{P(P_3) \cdot P(E \,|\, P_3)}{P(E)}.\]
3. Determine Prior Probabilities:
Given the ratio \( 4 : 1 : 2 \):
\[P(P_1) = \frac{4}{7}, \quad P(P_2) = \frac{1}{7}, \quad P(P_3) = \frac{2}{7}.\]
4. Compute Total Probability of Event \( E \):
\[P(E) = P(P_1) \cdot P(E \,|\, P_1) + P(P_2) \cdot P(E \,|\, P_2) + P(P_3) \cdot P(E \,|\, P_3).\]
Substitute the given values:
\[P(E) = \frac{4}{7} \cdot 0.3 + \frac{1}{7} \cdot 0.8 + \frac{2}{7} \cdot 0.5.\]
Simplify:
\[P(E) = \frac{1.2}{7} + \frac{0.8}{7} + \frac{1.0}{7} = \frac{3.0}{7}.\]
5. Calculate \( P(P_3 \,|\, E) \):
\[P(P_3 \,|\, E) = \frac{P(P_3) \cdot P(E \,|\, P_3)}{P(E)}.\]
Substitute values:
\[P(P_3 \,|\, E) = \frac{\frac{2}{7} \cdot 0.5}{\frac{3.0}{7}} = \frac{1.0}{3.0} = \frac{1}{3}.\]
Final Result:
The probability that the profit increase is a result of \( R \)'s CEO appointment is \( \boxed{\frac{1}{3}} \).