The centre of the circle whose radius is 3 units and touching internally the circle $x^2 + y^2 - 4x - 6y - 12 = 0$ at the point $(-1, -1)$ is
Show Hint
For circles touching internally, the point of tangency lies on the line joining the centers and divides the segment formed by the centers externally in the ratio of their radii. The distance between centers is $|r_1 - r_2|$.