Question:medium

The average of marks obtained by 120 candidates in a certain examination is 35. If the average marks of passed candidates is 39 and that of the failed candidates is 15, what is the number of candidates who passed the examination?

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When two groups have different averages, use total \(=\) (avg\(_1\)\(\times\)size\(_1\)) \(+\) (avg\(_2\)\(\times\)size\(_2\)), or set up a weighted-average equation and solve for the group size.

Updated On: Jul 16, 2026
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The Correct Option is C

Solution and Explanation

Step 1: The total marks of all 120 candidates \(=120\times35=4200\).

Step 2: Let \(p\) be the number of passed candidates, so \((120-p)\) failed. Then \(39p+15(120-p)=4200\).

Step 3: Expanding, \(39p+1800-15p=4200\), so \(24p=2400\), giving \(p=100\). \[ \boxed{100} \]
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