Question:medium

The average marks in English subject of a class of 24 students is 56. If the marks of three students were misread as 44, 45 and 61 of the actual marks 48, 59 and 67 respectively, then what would be the correct average?

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Find how much the actual marks exceed the misread marks in total, then spread that excess across all 24 students.
Updated On: Jul 16, 2026
  • 56.5
  • 59
  • 57.5
  • None of these
Show Solution

The Correct Option is D

Solution and Explanation

This can also be verified by rebuilding the total marks of the class from scratch instead of using the shortcut of adjusting the average directly.

Total marks of the class as originally (wrongly) recorded $= 56 \times 24 = 1344$.

To correct this total, remove the misread marks and add back the actual marks: corrected total $= 1344 - (44+45+61) + (48+59+67) = 1344 - 150 + 174 = 1368$.

Corrected average $= \dfrac{1368}{24} = 57$.

Since 57 does not match any of 56.5, 59 or 57.5, the correct choice is option D, "None of these".

\[\boxed{57}\]
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