Question:medium

The area of the region bounded by \(y = \sqrt{x}, y = -x\), and \(x = 4\) (in square units) is

Show Hint

When a region is bounded by a curve above the x-axis and another below it, the area is simply the sum of the magnitudes of the areas under each curve. Area = \(\int_0^4 \sqrt{x} dx + \int_0^4 |-x| dx = 16/3 + 8 = 40/3\).
Updated On: Jun 24, 2026
  • \(\frac{8}{3}\)
  • \(\frac{20}{3}\)
  • \(\frac{40}{3}\)
  • \(\frac{26}{3}\)
Show Solution

The Correct Option is C

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