Question:medium
The area in square units enclosed by the curve $x^{2}y = 36$, the $x$-axis and the lines $x = 6$ and $x = 9$ is
The area in square units enclosed by the curve $x^{2}y = 36$, the $x$-axis and the lines $x = 6$ and $x = 9$ is
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Area under a curve between two vertical lines: $A = \displaystyle\int_a^b y\,dx$. Simplify the integrand before integrating.
Updated On: Apr 8, 2026
- 2 sq unit
- 1 sq unit
- 4 sq unit
- 3 sq unit
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The Correct Option is A
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