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The area bounded by the x-axis, the curve \(y=f(x)\) and the lines \(x=1,\;x=b\) is equal to \(\sqrt{b^2+1}-\sqrt{2}\) for all \(b > 1\). Then \(f(x)\) is

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Differentiate area function to recover the integrand.

Updated On: Mar 24, 2026

\(\sqrt{x-1}\)
\(\sqrt{x+1}\)
\(\sqrt{x^2+1}\)
\(\dfrac{x}{\sqrt{1+x^2}}\)

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The Correct Option is D

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