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List of top Mathematics Questions on applications of integrals asked in BITSAT
The area under the curve y=|cos x-sin x|, 0≤ x≤ (π)/(2), above the x-axis is
BITSAT - 2021
BITSAT
Mathematics
applications of integrals
The area of the region
\[ R = \{(x, y) \mid |x| \le |y| \text{ and } x^2 + y^2 \le 1\} \]
is:
BITSAT - 2019
BITSAT
Mathematics
applications of integrals
The area under the curve \(y = |\cos x - \sin x|\), for \(0 \le x \le \frac{\pi}{2}\), and above the x-axis is
BITSAT - 2017
BITSAT
Mathematics
applications of integrals
The area of the region \(R=\{(x,y):|x|\le |y| \text{ and x^2+y^2\le1\}\) is
BITSAT - 2015
BITSAT
Mathematics
applications of integrals
The area bounded by the x-axis, the curve \(y=f(x)\) and the lines \(x=1,\;x=b\) is equal to \(\sqrt{b^2+1}-\sqrt{2}\) for all \(b > 1\). Then \(f(x)\) is
BITSAT - 2014
BITSAT
Mathematics
applications of integrals
The area intercepted by the curves \( y = \cos x \), \( x \in [0, \pi] \) and \( y = \cos 2x \), \( x \in [0, \pi] \), is
BITSAT - 2013
BITSAT
Mathematics
applications of integrals
The area bounded by the curve \( y = \sin x \), x-axis and the ordinates \( x = 0 \) and \( x = \pi/2 \) is:
BITSAT - 2012
BITSAT
Mathematics
applications of integrals
What is the area bounded by y=tan x, y=0 and x=(π)/(4)?
BITSAT - 2011
BITSAT
Mathematics
applications of integrals
The area of the region bounded by the curve y=x|x|, x-axis and the ordinates x=1, x=-1 is given by
BITSAT - 2010
BITSAT
Mathematics
applications of integrals
The minimum value of the function y=x⁴-2x²+1 in the interval [-\frac12,2] is
BITSAT - 2009
BITSAT
Mathematics
applications of integrals
The value of a in order that
f(x)= x- x-ax+b
decreases for all real values is
BITSAT - 2009
BITSAT
Mathematics
applications of integrals