To determine the activation energy of a chemical reaction, we often utilize the Arrhenius equation. The Arrhenius equation is given by:
k = A e^{-E_a/(RT)}
where:
The equation can be rearranged to a linear form as follows:
\ln(k) = \ln(A) - \frac{E_a}{R}\left(\frac{1}{T}\right)
This is a straight-line equation of the form y = mx + c, where y = \ln(k), m = -\frac{E_a}{R}, and x = \frac{1}{T}. This means that by plotting \ln(k) against \frac{1}{T}, the slope of the line will be -\frac{E_a}{R}.
Therefore, if you calculate the rate constants k_1 and k_2 at two different temperatures T_1 and T_2, respectively, you can use the following form to determine the activation energy:
\ln\left(\frac{k_2}{k_1}\right) = \frac{E_a}{R}\left(\frac{1}{T_1} - \frac{1}{T_2}\right)
Solving this equation for E_a gives:
E_a = R \cdot \ln\left(\frac{k_2}{k_1}\right) \cdot \left(\frac{1}{T_1} - \frac{1}{T_2}\right)^{-1}
Thus, the correct answer is to determine the activation energy by evaluating rate constants at two different temperatures.