Sugar worth 15 per kg and 16 per kg is mixed with a third variety of some other cost in the ratio 1 : 1 : 2. If the mixture is of worth 20 per kg, what would be the cost of the third variety of sugar per kg?

Question

A certain amount of water was poured into a 300 litre container and the remaining portion of the container was filled with milk. Then an amount of this solution was taken out from the container which was twice the volume of water that was earlier poured into it, and water was poured to refill the container again. If the resulting solution contains 72% milk, then the amount of water, in litres, that was initially poured into the container was

Answer 1

The correct answer is option (E):

24.5

Here's how to solve this problem:

Let's break it down using the concept of weighted averages. Since we have a ratio of 1:1:2 for the three varieties of sugar, let's assume we have 1 kg of the first type, 1 kg of the second type, and 2 kg of the third type.

* **Cost of the first type:** 1 kg * 15/kg = 15
* **Cost of the second type:** 1 kg * 16/kg = 16
* **Let 'x' be the cost of the third type:** 2 kg * x/kg = 2x

The total cost of the mixture is 15 + 16 + 2x = 31 + 2x
The total weight of the mixture is 1 kg + 1 kg + 2 kg = 4 kg
The average cost of the mixture is 20/kg

The formula for the average cost is (Total cost) / (Total weight).

So, we can write the equation: (31 + 2x) / 4 = 20

Now, solve for x:

1. Multiply both sides by 4: 31 + 2x = 80
2. Subtract 31 from both sides: 2x = 49
3. Divide both sides by 2: x = 24.5

Therefore, the cost of the third variety of sugar per kg is 24.5

Sugar worth 15 per kg and 16 per kg is mixed with a third variety of some other cost in the ratio 1 : 1 : 2. If the mixture is of worth 20 per kg, what would be the cost of the third variety of sugar per kg?

The Correct Option is

Solution and Explanation

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