Mixture A has a volume of \(200 \, \text{ml}\). This mixture contains \(120 \, \text{ml}\) of cocoa (\(60\%\)) and \(80 \, \text{ml}\) of sugar (\(40\%\)).
Mixture B has a volume of \(300 \, \text{ml}\). This mixture contains \(210 \, \text{ml}\) of coffee (\(70\%\)) and \(90 \, \text{ml}\) of sugar (\(30\%\)).
When mixtures A and B are combined in a \(2:3\) ratio, 200 ml of A and 300 ml of B are used. The resulting mixture C has a total volume of \(500 \, \text{ml}\) (\(200 + 300\)). The total amount of sugar in mixture C is \(170 \, \text{ml}\) (\(80 + 90\)).
Mixture C is then combined with an equal volume of milk. The final volume is \(1000 \, \text{ml}\) (\(500 + 500\)), and the sugar content remains \(170 \, \text{ml}\).
The percentage of sugar in the final mixture is calculated as follows:
\[ \frac{170}{1000} \times 100 = 17\% \]
Correct Option: (C) 17%