Question:medium

Statement-I : The electronegativity order in F, O, N is $F > O > N$.
Statement-II : Oxidation state of O in $OF_2$ is $+2$ and in $Na_2O$ is $-2$. Choose the correct option.

Updated On: Apr 5, 2026

Both statement-I \& statement-II are correct.
Both statement-I \& statement-II are incorrect.
Statement-I is correct \& statement-II is incorrect.
Statement-I is incorrect \& statement-II is correct.

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The Correct Option is A

Solution and Explanation

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Statement-I : The electronegativity order in F, O, N is \(F > O > N\).
Statement-II : Oxidation state of O in \(OF_2\) is \(+2\) and in \(Na_2O\) is \(-2\). Choose the correct option.

The Correct Option is A

Solution and Explanation

Top Questions on Inorganic chemistry

Questions Asked in JEE Main exam

Statement-I : The electronegativity order in F, O, N is \(F > O > N\). Statement-II : Oxidation state of O in \(OF_2\) is \(+2\) and in \(Na_2O\) is \(-2\). Choose the correct option.

The Correct Option is A

Solution and Explanation

Top Questions on Inorganic chemistry

Questions Asked in JEE Main exam

Statement-I : The electronegativity order in F, O, N is \(F > O > N\).
Statement-II : Oxidation state of O in \(OF_2\) is \(+2\) and in \(Na_2O\) is \(-2\). Choose the correct option.