Question:medium

State the number of significant figures in the following : 
(a) 0.007 m2 (b) 2.64 × 1024 kg (c) 0.2370 g cm–3 (d) 6.320 J (e) 6.032 N m–2 (f) 0.0006032 m2

Updated On: Jan 19, 2026
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Solution and Explanation

Quick Rules for Significant Figures

  • All non-zero digits are significant
  • Zeros between non-zero digits are significant
  • Trailing zeros after decimal point are significant
  • Leading zeros before non-zero digits are not significant
  • Trailing zeros in whole numbers without decimal are ambiguous

Analysis of Given Measurements

MeasurementBreakdownSignificant FiguresCount
\(0.007 \, \text{m}^2\)Leading zeros (0.00) not significant
Only 7 is significant
71
\(2.64 \times 10^{24} \, \text{kg}\)Scientific notation: 2.64 has 3 digits
Exponent \(10^{24}\) exact
2.643
\(0.2370 \, \text{g cm}^{-3}\)Leading zero not significant
2370 all significant (trailing zeros after decimal)
23704
\(6.320 \, \text{J}\)All digits significant
Trailing zero after decimal significant
6.3204
\(6.032 \, \text{N m}^{-2}\)All digits significant
Trailing zero after decimal significant
6.0324
\(0.0006032 \, \text{m}^2\)Leading zeros (0.0006) not significant
032 all significant
60324

Summary: (a) 1, (b) 3, (c) 4, (d) 4, (e) 4, (f) 4 significant figures

Verification Examples

Test CaseRule AppliedResult
Why 0.007 = 1 sig fig?Leading zeros never count\(0.007 = 7 \times 10^{-3}\)
Why 0.2370 = 4 sig figs?Trailing zeros after decimal countDecimal place confirms precision
Why \(2.64 \times 10^{24}\) = 3 sig figs?Only mantissa (2.64) countedExponent is exact number
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