Question:medium

Solubility product of BaCl\(_2\) is \( 4 \times 10^{-9} \). Its solubility in mol/L would be:

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To calculate solubility from the solubility product, remember to account for the number of ions produced.
Updated On: Apr 22, 2026
  • \( 1 \times 10^{-3} \)
  • \( 1 \times 10^{-9} \)
  • \( 4 \times 10^{-27} \)
  • \( 1 \times 10^{-27} \)
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The Correct Option is A

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