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Application of derivatives
slope of the normal to th...
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medium
Slope of the normal to the curve \(x^{2/3}+y^{2/3}=2\) at the point \((1,1)\) is
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The slope of normal is the negative reciprocal of the slope of tangent. If tangent slope is \(-1\), then normal slope is \(1\).
AP ECET Ceramic Tech - 2025
AP ECET Ceramic Tech
Updated On:
May 7, 2026
\(-1\)
\(1\)
\(\frac{1}{2}\)
\(-\frac{1}{2}\)
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The Correct Option is
B
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