To solve this problem, let's analyze the given observations and deduction step by step:
- Observation I: S is taller than R.
- Observation II: Q is the shortest of all.
- Observation III: U is taller than only one student.
- Observation IV: T is taller than S but is not the tallest.
First, let's write down the status of each student based on the observations:
- As per Observation II, Q is the shortest, so we can place them at the bottom.
- Observation III tells us that U is taller than only Q, making U the second shortest.
- Observation I implies S is taller than R, so S > R.
- With Observation IV, T is taller than S, but not the tallest, which means S is taller than R: T > S > R.
Summarizing based on these observations gives us two fixed points and the following order:
- Q (1st - Shortest)
- U (2nd)
- R, S, T, P - Remaining positions need arrangement
Now, from Observation IV, T is taller than S but is not the tallest:
- This implies another student, possibly P, is taller than T, meaning T is the second tallest. Therefore, P is the tallest.
- The order from shortest to tallest is: Q, U, R, S, T, P.
This results in:
- Q (Shortest)
- U (2nd shortest)
- R (3rd)
- S (4th)
- T (5th)
- P (Tallest)
The question asks us to find who underline should represent, such that the number of students taller and shorter than this person are equal. Here, in this order:
- For R, there are two students (S, T, P) taller and two students (Q, U) shorter, satisfying equality in number.
Thus, the correct answer is S as R should occupy the middle placement for it to have the same number of students taller and shorter than S, rather than him.