Question:medium

\(\sin 15^\circ \sin 45^\circ \sin 75^\circ =\)

Show Hint

Whenever you see angles like \(15^\circ\) and \(75^\circ\) in a product, always think of the identity \(\sin A \cos A = \frac{1}{2} \sin 2A\). It simplifies the calculation significantly.
Updated On: Jun 24, 2026
  • \(\frac{\sqrt{2}}{4}\)
  • \(\frac{\sqrt{2}}{2}\)
  • \(\frac{\sqrt{2}}{8}\)
  • \(-\frac{\sqrt{2}}{8}\)
  • \(-\frac{\sqrt{2}}{4}\)
Show Solution

The Correct Option is C

Solution and Explanation

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