Question:medium

$\sin^{-1}\dfrac{1}{\sqrt{5}} + \cos^{-1}\dfrac{3}{\sqrt{10}}$ is equal to

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$\tan^{-1}a + \tan^{-1}b = \tan^{-1}\!\left(\dfrac{a+b}{1-ab}\right)$ when $ab<1$. Convert $\sin^{-1}$ and $\cos^{-1}$ to $\tan^{-1}$ using right triangles.
Updated On: Apr 8, 2026
  • $\pi/6$
  • $\pi/4$
  • $\pi/3$
  • $2\pi/3$
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The Correct Option is B

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