Step 1: Goal.
We must turn benzoyl chloride into aniline, which means losing one carbon by a rearrangement.
Step 2: Working routes.
Ammonia then bromine and base gives a Hofmann rearrangement. Sodium azide gives a Curtius rearrangement. The oxime route gives a Beckmann path. All three reach aniline.
Step 3: The failing route.
Diazomethane does not give aniline, so that option is wrong.
Step 4: Answer.
\[ \boxed{\text{A, C and D}} \]