Sakshi starts from her college and walks 12 km towards the North. She then turns right and walks 5 km. After that, she turns right again and walks 4 km. She then turns left and walks 7 km. Finally, she turns left and walks 1 km. How far is Sakshi from her college and in which direction?
Show Hint
Always verify the final square root before selecting the option.
Here,
\[
9^2+12^2=81+144=225
\]
and
\[
\sqrt{225}=15,
\]
not 13. Also, \((9,12,15)\) is a multiple of the famous Pythagorean triplet \((3,4,5)\).
Hence, the correct option is (D) 15 km, North-East.
Step 1: Track Sakshi's movements step by step using coordinates. Start at $(0,0)$; move 12 km North: reach $(0,12)$; turn right (East), move 5 km: reach $(5,12)$; turn right (South), move 4 km: reach $(5,8)$; turn left (East), move 7 km: reach $(12,8)$; turn left (North), move 2 km: reach $(12,10)$. Step 2: Calculate net displacement components. Final position relative to start: East component = 12 km, North component = 10 km; both positive, so the final position is in the North-East direction from the starting point. Step 3: Calculate the magnitude of displacement. Distance $= \sqrt{12^2 + 10^2} = \sqrt{144 + 100} = \sqrt{244} \approx 15.6$ km; the closest option is approximately 15 km North-East. \[ \boxed{15 \text{ km NE (approx)}} \]
