To identify the most frequently visited station, the patrol routes will be analyzed under the specified conditions:
Based on this, the probable routes are derived:
Analysis indicates Station E is the most common destination:
Consequently, Station E is confirmed as the most visited.
At 09:00, all four teams departed Station A via distinct routes, ensuring no street simultaneously hosted multiple teams moving in the same direction.
By 10:00, Team 2 was at Station E, and Team 3 was at Station D. Concurrently, only Team 1 and Team 4 traversed the segment between Stations A and E.
This indicates Team 2 proceeded to E via F, and Team 3 to D via C. At 10:30, only Teams 1 and 3 were at Station E. Team 4, avoiding B, D, and F, confined its movement to Stations A, E, and C.
Consequently, Team 4's sole feasible path to reach E by 11:30 was:
Route: (A → E → A → C → A → E → A)
Team 1's complete trajectory was:
Route: (A → B → A → E → A → B → A)
Team 3 returned to Station A by 12:00 via:
Route: (A → C → D → E → D → C → A)
Team 2 was restricted to the remaining available route: (A → F → E → F → A or E → F → A)
| Teams | 9:00 | 9:30 | 10:00 | 10:30 | 11:00 | 11:30 | 12:00 |
|---|---|---|---|---|---|---|---|
| Team 1 | A | B | A | E | A | B | A |
| Team 2 | A | F | E | F | A / E | F | A |
| Team 3 | A | C | D | E | D | C | A |
| Team 4 | A | E | A | C | A | E | A |
Station B was exclusively visited by Team 1, and this occurred on two occasions:
Therefore, the total number of visits to Station B is:
\[ \boxed{2} \]
Based on these facts, the following timeline is established:
Consequently, Team 3 patrolled the street connecting Stations D and E at 10:15 hrs.
Given:
At 9:00 a.m., all four teams depart from Station A via distinct routes.
At 10:00 a.m.:
- Team 2 is at Station E.
- Team 3 is at Station D.
- Only Team 1 and Team 4 use the street connecting A and E.
Deductions for routes at 10:00 a.m.:
Team 2 route: $A \rightarrow F \rightarrow E$
Team 3 route: $A \rightarrow C \rightarrow D$
At 10:30 a.m., Teams 1 and 3 are at Station E.
Team 4's movement is restricted to Stations A, E, and C, avoiding B, D, and F.
Potential paths for Team 4 to reach E by 11:30 a.m.:
- $A \rightarrow E \rightarrow A \rightarrow C \rightarrow A \rightarrow E$
- $A \rightarrow E \rightarrow A \rightarrow E \rightarrow A \rightarrow E$
However, Team 1 occupied the A–E path at 10:00 a.m., preventing Team 4 from using it then.
Therefore, Team 4's required path is: $A \rightarrow E \rightarrow A \rightarrow C \rightarrow A \rightarrow E$
At 12:00 p.m., Team 4 returns to A from E: $E \rightarrow A$
Team 4's complete path: $A \rightarrow E \rightarrow A \rightarrow C \rightarrow A \rightarrow E \rightarrow A$
| Team | 9:00 | 9:30 | 10:00 | 10:30 | 11:00 | 11:30 | 12:00 |
|---|---|---|---|---|---|---|---|
| 1 | A | B | A | E | A | B | A |
| 2 | A | F | E | F | A/E | F | A |
| 3 | A | C | D | E | D | C | A |
| 4 | A | E | A | C | A | E | A |
Team 1 follows a loop: $A \rightarrow B \rightarrow A \rightarrow E \rightarrow A \rightarrow B \rightarrow A$
Team 2 has multiple path options, e.g.: $A \rightarrow F \rightarrow E \rightarrow F \rightarrow A$ or routes involving E multiple times.
Team 3's path: $A \rightarrow C \rightarrow D \rightarrow E \rightarrow D \rightarrow C \rightarrow A$
Only Team 4 passes through Station E exactly twice.
Correct Answer: 2