Question:medium

R-CH\(_2\)OH is converted into R-CHO by reacting with ______
 

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Remember the classification of oxidizing agents. Strong agents like KMnO\(_4\) and K\(_2\)Cr\(_2\)O\(_7\) oxidize primary alcohols to carboxylic acids. Mild agents like PCC and PDC (Pyridinium Dichromate) stop the oxidation at the aldehyde stage.
Updated On: Apr 28, 2026
  • Alkaline KMnO\(_4\)
  • LiAlH\(_4\)
  • Na/C\(_2\)H\(_5\)OH
  • PCC (Pyridinium Chlorochromate)
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The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept:
Primary alcohols ($R-CH_{2}OH$) can be oxidized to aldehydes ($R-CHO$) or carboxylic acids ($R-COOH$). To stop the oxidation at the aldehyde stage, a mild oxidizing agent is required.
Step 2: Key Formula or Approach:
Analyze the oxidizing/reducing strength of each given reagent to identify the one that specifically halts oxidation at the aldehyde stage without over-oxidizing the compound.
Step 3: Detailed Explanation:
(A) Alkaline KMnO$_{4}$ is a strong oxidizing agent that oxidizes primary alcohols directly to carboxylic acids.
(B) LiAlH$_{4}$ is a reducing agent, typically used to convert carbonyl compounds back to alcohols.
(C) Na/C$_{2}$H$_{5}$OH is a reducing agent (Bouveault-Blanc reduction).
(D) Pyridinium chlorochromate (PCC) is a specialized mild reagent that selectively oxidizes primary alcohols to aldehydes without further oxidation to carboxylic acids in anhydrous media.
Step 4: Final Answer:
The reagent used for the controlled oxidation of a primary alcohol to an aldehyde is PCC.
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